372=3x^2-5x

Solution for 372=3x^2-5x equation:

372=3x^2-5x

We move all terms to the left:

372-(3x^2-5x)=0

We get rid of parentheses

-3x^2+5x+372=0

a = -3; b = 5; c = +372;
Δ = b2-4ac
Δ = 52-4·(-3)·372
Δ = 4489
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4489}=67$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-67}{2*-3}=\frac{-72}{-6}
=+12
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+67}{2*-3}=\frac{62}{-6}
=-10+1/3
$